Optimal. Leaf size=735 \[ -\frac{5 b^{5/2} \sqrt [4]{c} \sqrt{1-\frac{d x^2}{c}} (b c-3 a d) \Pi \left (-\frac{\sqrt{b} \sqrt{c}}{\sqrt{a} \sqrt{d}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )\right |-1\right )}{4 a^{5/2} \sqrt [4]{d} e^{3/2} \sqrt{c-d x^2} (b c-a d)^3}+\frac{5 b^{5/2} \sqrt [4]{c} \sqrt{1-\frac{d x^2}{c}} (b c-3 a d) \Pi \left (\frac{\sqrt{b} \sqrt{c}}{\sqrt{a} \sqrt{d}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )\right |-1\right )}{4 a^{5/2} \sqrt [4]{d} e^{3/2} \sqrt{c-d x^2} (b c-a d)^3}+\frac{d \left (-7 a^2 d^2+19 a b c d+3 b^2 c^2\right )}{6 a c^2 e \sqrt{e x} \sqrt{c-d x^2} (b c-a d)^3}-\frac{\sqrt{c-d x^2} \left (-7 a^3 d^3+19 a^2 b c d^2-12 a b^2 c^2 d+5 b^3 c^3\right )}{2 a^2 c^3 e \sqrt{e x} (b c-a d)^3}+\frac{\sqrt [4]{d} \sqrt{1-\frac{d x^2}{c}} \left (-7 a^3 d^3+19 a^2 b c d^2-12 a b^2 c^2 d+5 b^3 c^3\right ) F\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )\right |-1\right )}{2 a^2 c^{9/4} e^{3/2} \sqrt{c-d x^2} (b c-a d)^3}-\frac{\sqrt [4]{d} \sqrt{1-\frac{d x^2}{c}} \left (-7 a^3 d^3+19 a^2 b c d^2-12 a b^2 c^2 d+5 b^3 c^3\right ) E\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )\right |-1\right )}{2 a^2 c^{9/4} e^{3/2} \sqrt{c-d x^2} (b c-a d)^3}+\frac{b}{2 a e \sqrt{e x} \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2} (b c-a d)}+\frac{d (2 a d+3 b c)}{6 a c e \sqrt{e x} \left (c-d x^2\right )^{3/2} (b c-a d)^2} \]
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Rubi [A] time = 4.75141, antiderivative size = 735, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 14, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.467 \[ -\frac{5 b^{5/2} \sqrt [4]{c} \sqrt{1-\frac{d x^2}{c}} (b c-3 a d) \Pi \left (-\frac{\sqrt{b} \sqrt{c}}{\sqrt{a} \sqrt{d}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )\right |-1\right )}{4 a^{5/2} \sqrt [4]{d} e^{3/2} \sqrt{c-d x^2} (b c-a d)^3}+\frac{5 b^{5/2} \sqrt [4]{c} \sqrt{1-\frac{d x^2}{c}} (b c-3 a d) \Pi \left (\frac{\sqrt{b} \sqrt{c}}{\sqrt{a} \sqrt{d}};\left .\sin ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )\right |-1\right )}{4 a^{5/2} \sqrt [4]{d} e^{3/2} \sqrt{c-d x^2} (b c-a d)^3}+\frac{d \left (-7 a^2 d^2+19 a b c d+3 b^2 c^2\right )}{6 a c^2 e \sqrt{e x} \sqrt{c-d x^2} (b c-a d)^3}-\frac{\sqrt{c-d x^2} \left (-7 a^3 d^3+19 a^2 b c d^2-12 a b^2 c^2 d+5 b^3 c^3\right )}{2 a^2 c^3 e \sqrt{e x} (b c-a d)^3}+\frac{\sqrt [4]{d} \sqrt{1-\frac{d x^2}{c}} \left (-7 a^3 d^3+19 a^2 b c d^2-12 a b^2 c^2 d+5 b^3 c^3\right ) F\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )\right |-1\right )}{2 a^2 c^{9/4} e^{3/2} \sqrt{c-d x^2} (b c-a d)^3}-\frac{\sqrt [4]{d} \sqrt{1-\frac{d x^2}{c}} \left (-7 a^3 d^3+19 a^2 b c d^2-12 a b^2 c^2 d+5 b^3 c^3\right ) E\left (\left .\sin ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )\right |-1\right )}{2 a^2 c^{9/4} e^{3/2} \sqrt{c-d x^2} (b c-a d)^3}+\frac{b}{2 a e \sqrt{e x} \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2} (b c-a d)}+\frac{d (2 a d+3 b c)}{6 a c e \sqrt{e x} \left (c-d x^2\right )^{3/2} (b c-a d)^2} \]
Antiderivative was successfully verified.
[In] Int[1/((e*x)^(3/2)*(a - b*x^2)^2*(c - d*x^2)^(5/2)),x]
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Rubi in Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/(e*x)**(3/2)/(-b*x**2+a)**2/(-d*x**2+c)**(5/2),x)
[Out]
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Mathematica [C] time = 3.59308, size = 582, normalized size = 0.79 \[ \frac{x \left (\frac{33 a b c d x^4 \left (7 a^3 d^3-19 a^2 b c d^2+12 a b^2 c^2 d-5 b^3 c^3\right ) F_1\left (\frac{7}{4};\frac{1}{2},1;\frac{11}{4};\frac{d x^2}{c},\frac{b x^2}{a}\right )}{2 x^2 \left (2 b c F_1\left (\frac{11}{4};\frac{1}{2},2;\frac{15}{4};\frac{d x^2}{c},\frac{b x^2}{a}\right )+a d F_1\left (\frac{11}{4};\frac{3}{2},1;\frac{15}{4};\frac{d x^2}{c},\frac{b x^2}{a}\right )\right )+11 a c F_1\left (\frac{7}{4};\frac{1}{2},1;\frac{11}{4};\frac{d x^2}{c},\frac{b x^2}{a}\right )}-\frac{49 a c x^2 \left (7 a^4 d^4-19 a^3 b c d^3+12 a^2 b^2 c^2 d^2-20 a b^3 c^3 d+5 b^4 c^4\right ) F_1\left (\frac{3}{4};\frac{1}{2},1;\frac{7}{4};\frac{d x^2}{c},\frac{b x^2}{a}\right )}{2 x^2 \left (2 b c F_1\left (\frac{7}{4};\frac{1}{2},2;\frac{11}{4};\frac{d x^2}{c},\frac{b x^2}{a}\right )+a d F_1\left (\frac{7}{4};\frac{3}{2},1;\frac{11}{4};\frac{d x^2}{c},\frac{b x^2}{a}\right )\right )+7 a c F_1\left (\frac{3}{4};\frac{1}{2},1;\frac{7}{4};\frac{d x^2}{c},\frac{b x^2}{a}\right )}-\frac{7 \left (a^4 d^3 \left (12 c^2-35 c d x^2+21 d^2 x^4\right )-a^3 b d^2 \left (36 c^3-83 c^2 d x^2+22 c d^2 x^4+21 d^3 x^6\right )+a^2 b^2 c d \left (36 c^3-36 c^2 d x^2-59 c d^2 x^4+57 d^3 x^6\right )-12 a b^3 c^2 \left (c-d x^2\right )^2 \left (c+3 d x^2\right )+15 b^4 c^3 x^2 \left (c-d x^2\right )^2\right )}{c-d x^2}\right )}{42 a^2 c^3 (e x)^{3/2} \left (a-b x^2\right ) \sqrt{c-d x^2} (a d-b c)^3} \]
Warning: Unable to verify antiderivative.
[In] Integrate[1/((e*x)^(3/2)*(a - b*x^2)^2*(c - d*x^2)^(5/2)),x]
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Maple [B] time = 0.079, size = 6334, normalized size = 8.6 \[ \text{output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/(e*x)^(3/2)/(-b*x^2+a)^2/(-d*x^2+c)^(5/2),x)
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (b x^{2} - a\right )}^{2}{\left (-d x^{2} + c\right )}^{\frac{5}{2}} \left (e x\right )^{\frac{3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b*x^2 - a)^2*(-d*x^2 + c)^(5/2)*(e*x)^(3/2)),x, algorithm="maxima")
[Out]
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b*x^2 - a)^2*(-d*x^2 + c)^(5/2)*(e*x)^(3/2)),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(e*x)**(3/2)/(-b*x**2+a)**2/(-d*x**2+c)**(5/2),x)
[Out]
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GIAC/XCAS [A] time = 1.2428, size = 1, normalized size = 0. \[ \mathit{Done} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b*x^2 - a)^2*(-d*x^2 + c)^(5/2)*(e*x)^(3/2)),x, algorithm="giac")
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